Important role than mathematics. Mathematics also should overcome the dangers of superstitions. An owner of a major strip casino once experienced a streak of losing substantial amounts of money to a few 'high rollers.' He did not attribute this losing streak to normal volatility in the games, but to bad luck. His solution was simple.
- Roulette Mathematics If you want to excel at roulette, then you really need to understand the maths behind it. True odds are the real world chance of a certain outcome, whereas the house odds are the payout ratio for the same scenario and are typically slightly lower.
- Definitive, and extensively revised and updated 3rd edition on the history, theory, practice and mathematics of bookmaking, plus the mathematics of off-course betting, bets and their computation and liability control. Further reading 'Finding an Edge', Ron Loftus, US-SC-North Charleston: Create Space., 2011, 144pp.
- A Roulette wheel is a traditional symbol for a system whose. 'the voice of JPL.' Behind the scenes, he was involved in many missions. Thorp had became a professor of mathematics at U.C.
- But most importantly I found that you don't need to have so many variables to predict roulette spins. The physics and mathematics behind winning roulette is relatively simple, and there are relatively few variables to consider. Winning Roulette really isn't rocket science, it is actually quite simple.
In gambling parlance, making a book is the practice of laying bets on the various possible outcomes of a single event. The term originates from the practice of recording such wagers in a hard-bound ledger (the 'book') and gives the English language the term bookmaker for the person laying the bets and thus 'making the book'.[1][2]
Making a 'book' (and the notion of overround)[edit]
A bookmaker strives to accept bets on the outcome of an event in the right proportions in order to make a profit regardless of which outcome prevails. See Dutch book and coherence (philosophical gambling strategy). This is achieved primarily by adjusting what are determined to be the true odds of the various outcomes of an event in a downward fashion (i.e. the bookmaker will pay out using his actual odds, an amount which is less than the true odds would have paid, thus ensuring a profit).[3]
The odds quoted for a particular event may be fixed but are more likely to fluctuate in order to take account of the size of wagers placed by the bettors in the run-up to the actual event (e.g. a horse race). This article explains the mathematics of making a book in the (simpler) case of the former event. For the second method, see Parimutuel betting.
It is important to understand the relationship between fractional and decimal odds. Fractional odds are those written a-b (a/b or a to b) mean a winning bettor will receive their money back plus a units for every b units they bet. Multiplying both a and b by the same number gives odds equivalent to a-b. Decimal odds are a single value, greater than 1, representing the amount to be paid out for each unit bet. For example, a bet of £40 at 6-4 (fractional odds) will pay out £40 + £60 = £100. The equivalent decimal odds are 2.5; £40 x 2.5 = £100. We can convert fractional to decimal odds by the formula D=b+a⁄b. Hence, fractional odds of a-1 (ie. b=1) can be obtained from decimal odds by a=D-1.
It is also important to understand the relationship between odds and implied probabilities:Fractional odds of a-b (with corresponding decimal odds D) represent an implied probability of b⁄a+b=1⁄D, e.g. 6-4 corresponds to 4⁄6+4 = 4⁄10 = 0.4 (40%).An implied probability of x is represented by fractional odds of (1-x)/x, e.g. 0.2 is (1-0.2)/0.2 = 0.8/0.2 = 4/1 (4-1, 4 to 1) (equivalently, 1⁄x - 1 to 1), and decimal odds of D=1⁄x.
Example[edit]
In considering a football match (the event) that can be either a 'home win', 'draw' or 'away win' (the outcomes) then the following odds might be encountered to represent the true chance of each of the three outcomes:
- Home: Evens
- Draw: 2-1
- Away: 5-1
These odds can be represented as implied probabilities (or percentages by multiplying by 100) as follows:
- Evens (or 1-1) corresponds to an implied probability of 1⁄2 (50%)
- 2-1 corresponds to an implied probability of 1⁄3 (331⁄3%)
- 5-1 corresponds to an implied probability of 1⁄6 (162⁄3%)
By adding the percentages together a total 'book' of 100% is achieved (representing a fair book). The bookmaker, in his wish to avail himself of a profit, will invariably reduce these odds. Consider the simplest model of reducing, which uses a proportional decreasing of odds. For the above example, the following odds are in the same proportion with regard to their implied probabilities (3:2:1):
- Home: 4-6
- Draw: 6-4
- Away: 4-1
- 4-6 corresponds to an implied probability of 3⁄5 (60%)
- 6-4 corresponds to an implied probability of 2⁄5 (40%)
- 4-1 corresponds to an implied probability of 1⁄5 (20%)
By adding these percentages together a 'book' of 120% is achieved.
The amount by which the actual 'book' exceeds 100% is known as the 'overround',[4][5] 'bookmaker margin' [3] or the 'vigorish' or 'vig':[3] it represents the bookmaker's expected profit.[3] Thus, in an 'ideal' situation, if the bookmaker accepts £120 in bets at his own quoted odds in the correct proportion, he will pay out only £100 (including returned stakes) no matter what the actual outcome of the football match.Examining how he potentially achieves this:
- A stake of £60.00 @ 4-6 returns £100.00 (exactly) for a home win.
- A stake of £40.00 @ 6-4 returns £100.00 (exactly) for a drawn match
- A stake of £20.00 @ 4-1 returns £100.00 (exactly) for an away win
Total stakes received — £120.00 and a maximum payout of £100.00 irrespective of the result. This £20.00 profit represents a 162⁄3 % profit on turnover (20.00/120.00).
In reality, bookmakers use models of reducing that are more complicated than the model of the 'ideal' situation.
Bookmaker margin in English football leagues[edit]
Bookmaker margin in English football leagues decreased in recent years.[6] The study of six large bookmakers between 2005/06 season and 2017/2018 season showed that average margin in Premier League decreased from 9% to 4%, in English Football League Championship, English Football League One, and English Football League Two from 11% to 6%, and in National League from 11% to 8%.
Overround on multiple bets[edit]
When a punter (bettor) combines more than one selection in, for example, a double, treble or accumulator then the effect of the overround in the book of each selection is compounded to the detriment of the punter in terms of the financial return compared to the true odds of all of the selections winning and thus resulting in a successful bet.
To explain the concept in the most basic of situations an example consisting of a double made up of selecting the winner from each of two tennis matches will be looked at:
In Match 1 between players A and B both players are assessed to have an equal chance of winning. The situation is the same in Match 2 between players C and D. In a fair book in each of their matches, i.e. each has a book of 100%, all players would be offered at odds of Evens (1-1). However, a bookmaker would probably offer odds of 5-6 (for example) on each of the two possible outcomes in each event (each tennis match). This results in a book for each of the tennis matches of 109.09...%, calculated by 100 × (6⁄11 + 6⁄11) i.e. 9.09% overround.
There are four possible outcomes from combining the results from both matches: the winning pair of players could be AC, AD, BC or BD. As each of the outcomes for this example has been deliberately chosen to ensure that they are equally likely it can be deduced that the probability of each outcome occurring is 1⁄4 or 0.25 and that the fractional odds against each one occurring is 3-1. A bet of 100 units (for simplicity) on any of the four combinations would produce a return of 100 × (3/1 + 1) = 400 units if successful, reflecting decimal odds of 4.0.
The decimal odds of a multiple bet is often calculated by multiplying the decimal odds of the individual bets, the idea being that if the events are independent then the implied probability should be the product of the implied probabilities of the individual bets. In the above case with fractional odds of 5-6, the decimal odds are 11⁄6. So the decimal odds of the double bet is 11⁄6×11⁄6=1.833...×1.833...=3.3611..., or fractional odds of 2.3611-1. This represents an implied probability of 29.752% (1/3.3611) and multiplying by 4 (for each of the four equally likely combinations of outcomes) gives a total book of 119.01%. Thus the overround has slightly more than doubled by combining two single bets into a double.
In general, the combined overround on a double (OD), expressed as a percentage, is calculated from the individual books B1 and B2, expressed as decimals, by OD = B1 × B2 × 100 − 100.In the example we have OD = 1.0909 × 1.0909 × 100 − 100 = 19.01%.
This massive increase in potential profit for the bookmaker (19% instead of 9% on an event; in this case the double) is the main reason why bookmakers pay bonuses for the successful selection of winners in multiple bets: compare offering a 25% bonus on the correct choice of four winners from four selections in a Yankee, for example, when the potential overround on a simple fourfold of races with individual books of 120% is over 107% (a book of 207%). This is why bookmakers offer bets such as Lucky 15, Lucky 31 and Lucky 63; offering double the odds for one winner and increasing percentage bonuses for two, three and more winners.
In general, for any accumulator bet from two to i selections, the combined percentage overround of books of B1, B2, ..., Bi given in terms of decimals, is calculated by B1 × B2 × ... × Bi × 100 − 100. E.g. the previously mentioned fourfold consisting of individual books of 120% (1.20) gives an overround of 1.20 × 1.20 × 1.20 × 1.20 × 100 − 100 = 107.36%.
Settling winning bets[edit]
In settling winning bets either decimal odds are used or one is added to the fractional odds: this is to include the stake in the return. The place part of each-way bets is calculated separately from the win part; the method is identical but the odds are reduced by whatever the place factor is for the particular event (see Accumulator below for detailed example). All bets are taken as 'win' bets unless 'each-way' is specifically stated. All show use of fractional odds: replace (fractional odds + 1) by decimal odds if decimal odds known. Non-runners are treated as winners with fractional odds of zero (decimal odds of 1). Fractions of pence in total winnings are invariably rounded down by bookmakers to the nearest penny below. Calculations below for multiple-bet wagers result in totals being shown for the separate categories (e.g. doubles, trebles etc.), and therefore overall returns may not be exactly the same as the amount received from using the computer software available to bookmakers to calculate total winnings.[7][8]
Singles[edit]
Win single
E.g. £100 single at 9-2; total staked = £100
- Returns = £100 × (9/2 + 1) = £100 × 5.5 = £550
Each-way single
E.g. £100 each-way single at 11-4 ( 1⁄5 odds a place); total staked = £200
- Returns (win) = £100 × (11/4 + 1) = £100 × 3.75 = £375
- Returns (place) = £100 × (11/20 + 1) = £100 × 1.55 = £155
- Total returns if selection wins = £530; if only placed = £155
Multiple bets[edit]
Each-Way multiple bets are usually settled using a default 'Win to Win, Place to Place' method, meaning that the bet consists of a win accumulator and a separate place accumulator (Note: a double or treble is an accumulator with 2 or 3 selections respectively). However, a more uncommon way of settling these type of bets is 'Each-Way all Each-Way' (known as 'Equally Divided', which must normally be requested as such on the betting slip) in which the returns from one selection in the accumulator are split to form an equal-stake each-way bet on the next selection and so on until all selections have been used.[9][10] The first example below shows the two different approaches to settling these types of bets.
Double[11][12]
E.g. £100 each-way double with winners at 2-1 ( 1⁄5 odds a place) and 5-4 ( 1⁄4 odds a place); total staked = £200
- Returns (win double) = £100 × (2/1 + 1) × (5/4 + 1) = £675
- Returns (place double) = £100 × (2/5 + 1) × (5/16 + 1) = £183.75
- Total returns = £858.75
- Returns (first selection) = £100 × (2/1 + 1) + £100 × (2/5 + 1) = £440 which is split equally to give a £220 each-way bet on the second selection)
- Returns (second selection) = £220 × (5/4 + 1) + £220 × (5/16 + 1) = £783.75
- Total returns = £783.85
Note: 'Win to Win, Place to Place' will always provide a greater return if all selections win, whereas 'Each-Way all Each-Way' provides greater compensation if one selection is a loser as each of the other winners provide a greater amount of place money for subsequent selections.
Treble[11][12]
E.g. £100 treble with winners at 3-1, 4-6 and 11-4; total staked = £100
- Returns = £100 × (3/1 + 1) × (4/6 + 1) × (11/4 + 1) = £2500
Accumulator[11][12]
E.g. £100 each-way fivefold accumulator with winners at Evens ( 1⁄4 odds a place), 11-8 ( 1⁄5 odds), 5-4 ( 1⁄4 odds), 1-2 (all up to win) and 3-1 ( 1⁄5 odds); total staked = £200
Note: 'All up to win' means there are insufficient participants in the event for place odds to be given (e.g. 4 or fewer runners in a horse race). The only 'place' therefore is first place, for which the win odds are given.
- Returns (win fivefold) = £100 × (1/1 + 1) × (11/8 + 1) × (5/4 + 1) × (1/2 + 1) × (3/1 + 1) = £6412.50
- Returns (place fivefold) = £100 × (1/4 + 1) × (11/40 + 1) × (5/16 + 1) × (1/2 + 1) × (3/5 + 1) = £502.03
- Total returns = £6914.53
Full-cover bets[edit]
Trixie
- Returns (3 doubles) = £10 × [(4/7 + 1) × (2/1 + 1) + (4/7 + 1) × (11/10 + 1) + (2/1 + 1) × (11/10 + 1)] = £143.14
- Returns (1 treble) = £10 × (4/7 + 1) × (2/1 + 1) × (11/10 + 1) = £99.00
- Total returns = £242.14
Yankee
- Returns (6 doubles) = £10 × [(1/3 + 1) × (5/2 + 1) + (1/3 + 1) × (6/4 + 1) + (1/3 + 1) × (1/1 + 1) + (5/2 + 1) × (6/4 + 1) + (5/2 + 1) × (1/1 + 1) + (6/4 + 1) × (1/1 + 1)] = £314.16
- Returns (4 trebles) = £10 × [(1/3 + 1) × (5/2 + 1) × (6/4 + 1) + (1/3 + 1) × (5/2 + 1) × (1/1 + 1) + (1/3 + 1) × (6/4 + 1) × (1/1 + 1) + (5/2 + 1) × (6/4 + 1) × (1/1 + 1)] = £451.66
- Returns (1 fourfold) = £10 × (1/3 + 1) × (5/2 + 1) × (6/4 + 1) × (1/1 + 1) = £233.33
- Total returns = £999.15
Trixie, Yankee, Canadian, Heinz, Super Heinz and Goliath form a family of bets known as full cover bets which have all possible multiples present. Examples of winning Trixie and Yankee bets have been shown above. The other named bets are calculated in a similar way by looking at all the possible combinations of selections in their multiples. Note: A Double may be thought of as a full cover bet with only two selections.
Should a selection in one of these bets not win, then the remaining winners are treated as being a wholly successful bet on the next 'family member' down. For example, only two winners out of three in a Trixie means the bet is settled as a double; only four winners out of five in a Canadian means it is settled as a Yankee; only five winners out of eight in a Goliath means it is settled as a Canadian. The place part of each-way bets is calculated separately using reduced place odds. Thus, an each-way Super Heinz on seven horses with three winners and a further two placed horses is settled as a win Trixie and a place Canadian. Virtually all bookmakers use computer software for ease, speed and accuracy of calculation for the settling of multiples bets.
Full cover bets with singles[edit]
Patent
- Returns (3 singles) = £2 × [(4/6 + 1) + (2/1 + 1) + (11/4 + 1)] = £16.83
- Returns (3 doubles) = £2 × [(4/6 + 1) × (2/1 + 1) + (4/6 + 1) × (11/4 + 1) + (2/1 + 1) × (11/4 + 1)] = £45.00
- Returns (1 treble) = £2 × (4/6 + 1) × (2/1 + 1) × (11/4 + 1) = £37.50
- Total returns = £99.33
Patent, Lucky 15, Lucky 31, Lucky 63 and higher Lucky bets form a family of bets known as full cover bets with singles which have all possible multiples present together with single bets on all selections. An examples of a winning Patent bet has been shown above. The other named bets are calculated in a similar way by looking at all the possible combinations of selections in their multiples and singles.
Should a selection in one of these bets not win, then the remaining winners are treated as being a wholly successful bet on the next 'family member' down. For example, only two winners out of three in a Patent means the bet is settled as a double and two singles; only three winners out of four in a Lucky 15 means it is settled as a Patent; only four winners out of six in a Lucky 63 means it is settled as a Lucky 15. The place part of each-way bets is calculated separately using reduced place odds. Thus, an each-way Lucky 63 on six horses with three winners and a further two placed horses is settled as a win Patent and a place Lucky 31.
Algebraic interpretation[edit]
Returns on any bet may be considered to be calculated as 'stake unit' × 'odds multiplier'. The overall 'odds multiplier' is a combined decimal odds value and is the result of all the individual bets that make up a full cover bet, including singles if needed. E.g. if a successful £10 Yankee returned £461.35 then the overall 'odds multiplier' (OM) is 46.135.
If a, b, c, d... represent the decimal odds, i.e. (fractional odds + 1), then an OM can be calculated algebraically by multiplying the expressions (a + 1), (b + 1), (c + 1)... etc. together in the required manner and subtracting 1. If required, (decimal odds + 1) may be replaced by (fractional odds + 2).[13][14]
Examples[edit]
3 selections with decimal odds a, b and c.Expanding (a + 1)(b + 1)(c + 1) algebraically gives abc + ab + ac + bc + a + b + c + 1. This is equivalent to the OM for a Patent (treble: abc; doubles: ab, ac and bc; singles: a, b and c) plus 1.Therefore to calculate the returns for a winning Patent it is just a case of multiplying (a + 1), (b + 1) and (c + 1) together and subtracting 1 to get the OM for the winning bet, i.e. OM = (a + 1)(b + 1)(c + 1) − 1. Now multiply by the unit stake to get the total return on the bet.[15][16]
E.g. The winning Patent described earlier can be more quickly and simply evaluated by the following:
- Total returns = £2 × [(4/6 + 2) × (2/1 + 2) × (11/4 + 2) − 1] = £99.33
Ignoring any bonuses, a 50 pence each-way Lucky 63 (total stake £63) with 4 winners [2-1, 5-2, 7-2 (all 1⁄5 odds a place) and 6-4 (1⁄4 odds a place)] and a further placed horse [9-2 (1⁄5 odds a place)] can be relatively easily calculated as follows:
- Returns (win part) = 0.50 × [(2/1 + 2) × (5/2 + 2) × (7/2 + 2) × (6/4 + 2) − 1] = £172.75
- or more simply as 0.50 × (4 × 4.5 × 5.5 × 3.5 − 1)
The decimal odds of a multiple bet is often calculated by multiplying the decimal odds of the individual bets, the idea being that if the events are independent then the implied probability should be the product of the implied probabilities of the individual bets. In the above case with fractional odds of 5-6, the decimal odds are 11⁄6. So the decimal odds of the double bet is 11⁄6×11⁄6=1.833...×1.833...=3.3611..., or fractional odds of 2.3611-1. This represents an implied probability of 29.752% (1/3.3611) and multiplying by 4 (for each of the four equally likely combinations of outcomes) gives a total book of 119.01%. Thus the overround has slightly more than doubled by combining two single bets into a double.
In general, the combined overround on a double (OD), expressed as a percentage, is calculated from the individual books B1 and B2, expressed as decimals, by OD = B1 × B2 × 100 − 100.In the example we have OD = 1.0909 × 1.0909 × 100 − 100 = 19.01%.
This massive increase in potential profit for the bookmaker (19% instead of 9% on an event; in this case the double) is the main reason why bookmakers pay bonuses for the successful selection of winners in multiple bets: compare offering a 25% bonus on the correct choice of four winners from four selections in a Yankee, for example, when the potential overround on a simple fourfold of races with individual books of 120% is over 107% (a book of 207%). This is why bookmakers offer bets such as Lucky 15, Lucky 31 and Lucky 63; offering double the odds for one winner and increasing percentage bonuses for two, three and more winners.
In general, for any accumulator bet from two to i selections, the combined percentage overround of books of B1, B2, ..., Bi given in terms of decimals, is calculated by B1 × B2 × ... × Bi × 100 − 100. E.g. the previously mentioned fourfold consisting of individual books of 120% (1.20) gives an overround of 1.20 × 1.20 × 1.20 × 1.20 × 100 − 100 = 107.36%.
Settling winning bets[edit]
In settling winning bets either decimal odds are used or one is added to the fractional odds: this is to include the stake in the return. The place part of each-way bets is calculated separately from the win part; the method is identical but the odds are reduced by whatever the place factor is for the particular event (see Accumulator below for detailed example). All bets are taken as 'win' bets unless 'each-way' is specifically stated. All show use of fractional odds: replace (fractional odds + 1) by decimal odds if decimal odds known. Non-runners are treated as winners with fractional odds of zero (decimal odds of 1). Fractions of pence in total winnings are invariably rounded down by bookmakers to the nearest penny below. Calculations below for multiple-bet wagers result in totals being shown for the separate categories (e.g. doubles, trebles etc.), and therefore overall returns may not be exactly the same as the amount received from using the computer software available to bookmakers to calculate total winnings.[7][8]
Singles[edit]
Win single
E.g. £100 single at 9-2; total staked = £100
- Returns = £100 × (9/2 + 1) = £100 × 5.5 = £550
Each-way single
E.g. £100 each-way single at 11-4 ( 1⁄5 odds a place); total staked = £200
- Returns (win) = £100 × (11/4 + 1) = £100 × 3.75 = £375
- Returns (place) = £100 × (11/20 + 1) = £100 × 1.55 = £155
- Total returns if selection wins = £530; if only placed = £155
Multiple bets[edit]
Each-Way multiple bets are usually settled using a default 'Win to Win, Place to Place' method, meaning that the bet consists of a win accumulator and a separate place accumulator (Note: a double or treble is an accumulator with 2 or 3 selections respectively). However, a more uncommon way of settling these type of bets is 'Each-Way all Each-Way' (known as 'Equally Divided', which must normally be requested as such on the betting slip) in which the returns from one selection in the accumulator are split to form an equal-stake each-way bet on the next selection and so on until all selections have been used.[9][10] The first example below shows the two different approaches to settling these types of bets.
Double[11][12]
E.g. £100 each-way double with winners at 2-1 ( 1⁄5 odds a place) and 5-4 ( 1⁄4 odds a place); total staked = £200
- Returns (win double) = £100 × (2/1 + 1) × (5/4 + 1) = £675
- Returns (place double) = £100 × (2/5 + 1) × (5/16 + 1) = £183.75
- Total returns = £858.75
- Returns (first selection) = £100 × (2/1 + 1) + £100 × (2/5 + 1) = £440 which is split equally to give a £220 each-way bet on the second selection)
- Returns (second selection) = £220 × (5/4 + 1) + £220 × (5/16 + 1) = £783.75
- Total returns = £783.85
Note: 'Win to Win, Place to Place' will always provide a greater return if all selections win, whereas 'Each-Way all Each-Way' provides greater compensation if one selection is a loser as each of the other winners provide a greater amount of place money for subsequent selections.
Treble[11][12]
E.g. £100 treble with winners at 3-1, 4-6 and 11-4; total staked = £100
- Returns = £100 × (3/1 + 1) × (4/6 + 1) × (11/4 + 1) = £2500
Accumulator[11][12]
E.g. £100 each-way fivefold accumulator with winners at Evens ( 1⁄4 odds a place), 11-8 ( 1⁄5 odds), 5-4 ( 1⁄4 odds), 1-2 (all up to win) and 3-1 ( 1⁄5 odds); total staked = £200
Note: 'All up to win' means there are insufficient participants in the event for place odds to be given (e.g. 4 or fewer runners in a horse race). The only 'place' therefore is first place, for which the win odds are given.
- Returns (win fivefold) = £100 × (1/1 + 1) × (11/8 + 1) × (5/4 + 1) × (1/2 + 1) × (3/1 + 1) = £6412.50
- Returns (place fivefold) = £100 × (1/4 + 1) × (11/40 + 1) × (5/16 + 1) × (1/2 + 1) × (3/5 + 1) = £502.03
- Total returns = £6914.53
Full-cover bets[edit]
Trixie
- Returns (3 doubles) = £10 × [(4/7 + 1) × (2/1 + 1) + (4/7 + 1) × (11/10 + 1) + (2/1 + 1) × (11/10 + 1)] = £143.14
- Returns (1 treble) = £10 × (4/7 + 1) × (2/1 + 1) × (11/10 + 1) = £99.00
- Total returns = £242.14
Yankee
- Returns (6 doubles) = £10 × [(1/3 + 1) × (5/2 + 1) + (1/3 + 1) × (6/4 + 1) + (1/3 + 1) × (1/1 + 1) + (5/2 + 1) × (6/4 + 1) + (5/2 + 1) × (1/1 + 1) + (6/4 + 1) × (1/1 + 1)] = £314.16
- Returns (4 trebles) = £10 × [(1/3 + 1) × (5/2 + 1) × (6/4 + 1) + (1/3 + 1) × (5/2 + 1) × (1/1 + 1) + (1/3 + 1) × (6/4 + 1) × (1/1 + 1) + (5/2 + 1) × (6/4 + 1) × (1/1 + 1)] = £451.66
- Returns (1 fourfold) = £10 × (1/3 + 1) × (5/2 + 1) × (6/4 + 1) × (1/1 + 1) = £233.33
- Total returns = £999.15
Trixie, Yankee, Canadian, Heinz, Super Heinz and Goliath form a family of bets known as full cover bets which have all possible multiples present. Examples of winning Trixie and Yankee bets have been shown above. The other named bets are calculated in a similar way by looking at all the possible combinations of selections in their multiples. Note: A Double may be thought of as a full cover bet with only two selections.
Should a selection in one of these bets not win, then the remaining winners are treated as being a wholly successful bet on the next 'family member' down. For example, only two winners out of three in a Trixie means the bet is settled as a double; only four winners out of five in a Canadian means it is settled as a Yankee; only five winners out of eight in a Goliath means it is settled as a Canadian. The place part of each-way bets is calculated separately using reduced place odds. Thus, an each-way Super Heinz on seven horses with three winners and a further two placed horses is settled as a win Trixie and a place Canadian. Virtually all bookmakers use computer software for ease, speed and accuracy of calculation for the settling of multiples bets.
Full cover bets with singles[edit]
Patent
- Returns (3 singles) = £2 × [(4/6 + 1) + (2/1 + 1) + (11/4 + 1)] = £16.83
- Returns (3 doubles) = £2 × [(4/6 + 1) × (2/1 + 1) + (4/6 + 1) × (11/4 + 1) + (2/1 + 1) × (11/4 + 1)] = £45.00
- Returns (1 treble) = £2 × (4/6 + 1) × (2/1 + 1) × (11/4 + 1) = £37.50
- Total returns = £99.33
Patent, Lucky 15, Lucky 31, Lucky 63 and higher Lucky bets form a family of bets known as full cover bets with singles which have all possible multiples present together with single bets on all selections. An examples of a winning Patent bet has been shown above. The other named bets are calculated in a similar way by looking at all the possible combinations of selections in their multiples and singles.
Should a selection in one of these bets not win, then the remaining winners are treated as being a wholly successful bet on the next 'family member' down. For example, only two winners out of three in a Patent means the bet is settled as a double and two singles; only three winners out of four in a Lucky 15 means it is settled as a Patent; only four winners out of six in a Lucky 63 means it is settled as a Lucky 15. The place part of each-way bets is calculated separately using reduced place odds. Thus, an each-way Lucky 63 on six horses with three winners and a further two placed horses is settled as a win Patent and a place Lucky 31.
Algebraic interpretation[edit]
Returns on any bet may be considered to be calculated as 'stake unit' × 'odds multiplier'. The overall 'odds multiplier' is a combined decimal odds value and is the result of all the individual bets that make up a full cover bet, including singles if needed. E.g. if a successful £10 Yankee returned £461.35 then the overall 'odds multiplier' (OM) is 46.135.
If a, b, c, d... represent the decimal odds, i.e. (fractional odds + 1), then an OM can be calculated algebraically by multiplying the expressions (a + 1), (b + 1), (c + 1)... etc. together in the required manner and subtracting 1. If required, (decimal odds + 1) may be replaced by (fractional odds + 2).[13][14]
Examples[edit]
3 selections with decimal odds a, b and c.Expanding (a + 1)(b + 1)(c + 1) algebraically gives abc + ab + ac + bc + a + b + c + 1. This is equivalent to the OM for a Patent (treble: abc; doubles: ab, ac and bc; singles: a, b and c) plus 1.Therefore to calculate the returns for a winning Patent it is just a case of multiplying (a + 1), (b + 1) and (c + 1) together and subtracting 1 to get the OM for the winning bet, i.e. OM = (a + 1)(b + 1)(c + 1) − 1. Now multiply by the unit stake to get the total return on the bet.[15][16]
E.g. The winning Patent described earlier can be more quickly and simply evaluated by the following:
- Total returns = £2 × [(4/6 + 2) × (2/1 + 2) × (11/4 + 2) − 1] = £99.33
Ignoring any bonuses, a 50 pence each-way Lucky 63 (total stake £63) with 4 winners [2-1, 5-2, 7-2 (all 1⁄5 odds a place) and 6-4 (1⁄4 odds a place)] and a further placed horse [9-2 (1⁄5 odds a place)] can be relatively easily calculated as follows:
- Returns (win part) = 0.50 × [(2/1 + 2) × (5/2 + 2) × (7/2 + 2) × (6/4 + 2) − 1] = £172.75
- or more simply as 0.50 × (4 × 4.5 × 5.5 × 3.5 − 1)
- Returns (place part) = 0.50 × [(2/5 + 2) × (5/10 + 2) × (7/10 + 2) × (6/16 + 2) × (9/10 + 2) − 1] = £11.79
- or more simply as 0.50 × (2.4 × 2.5 × 2.7 × 2.375 × 2.9 − 1)
- Total returns = £184.54
For the family of full cover bets that do not include singles an adjustment to the calculation is made to leave just the doubles, trebles and accumulators. Thus, a previously described winning £10 Yankee with winners at 1-3, 5-2, 6-4 and Evens has returns calculated by:
- £10 × [(1/3 + 2) × (5/2 + 2) × (6/4 + 2) × (1/1 + 2) − 1 − [(1/3 + 1) + (5/2 + 1) + (6/4 + 1) + (1/1 + 1)]] = £999.16
In effect, the bet has been calculated as a Lucky 15 minus the singles. Note that the total returns value of £999.16 is a penny higher than the previously calculated value as this quicker method only involves rounding the final answer, and not rounding at each individual step.
In algebraic terms the OM for the Yankee bet is given by:
- OM = (a + 1)(b + 1)(c + 1)(d + 1) − 1 − (a + b + c + d)
In the days before software became available for use by bookmakers and those settling bets in Licensed Betting Offices (LBOs) this method was virtually de rigueur for saving time and avoiding the multiple repetitious calculations necessary in settling bets of the full cover type.
Settling other types of winning bets[edit]
Up and down
- Returns (£20 single at 7-2 ATC £20 single at 15-8) = £20 × 7/2 + £20 × (15/8 + 1) = £127.50
- Returns (£20 single at 15-8 ATC £20 single at 7-2) = £20 × 15/8 + £20 × (7/2 + 1) = £127.50
- Total returns = £255.00
- Note: This is the same as two £20 single bets at twice the odds; i.e. £20 singles at 7-1 and 15-4 and is the preferred manual way of calculating the bet.
- Returns (£10 single at 5-1 ATC £10 single on 'loser') = £10 × 5/1 = £50
- Note: This calculation of a bet where the stake is not returned is called 'receiving the odds to the stake' on the winner; in this case receiving the odds to £10 (on the 5-1 winner).
Round Robin
A Round Robin with 3 winners is calculated as a Trixie plus three Up and Down bets with 2 winners in each.
A Round Robin with 2 winners is calculated as a double plus one Up and Down bet with 2 winners plus two Up and Down bets with 1 winner in each.
A Round Robin with 1 winner is calculated as two Up and Down bets with one winner in each.
Flag and Super Flag bets may be calculated in a similar manner as above using the appropriate full cover bet (if sufficient winners) together with the required number of 2 winner- and 1 winner Up and Down bets.
Note: Expert bet settlers before the introduction of bet-settling software would have invariably used an algebraic-type method together with a simple calculator to determine the return on a bet (see below).
Algebraic interpretation[edit]
If a, b, c, d... represent the decimal odds, i.e. (fractional odds + 1), then an 'odds multiplier' OM can be calculated algebraically by multiplying the expressions (a + 1), (b + 1), (c + 1)... etc. together in the required manner and adding or subtracting additional components. If required, (decimal odds + 1) may be replaced by (fractional odds + 2).[13][14]
Examples[edit]
- OM (2 winners) = (2a − 1) + (2b − 1) = 2(a + b − 1)
- OM (1 winner) = a − 1
- OM (3 winners) = (a + 1) × (b + 1) × (c + 1) − 1 − (a + b + c) + 2 × [(a + b − 1) + (a + c − 1) + (b + c − 1)] = (a + 1)(b + 1)(c + 1) + 3(a + b + c) − 7
- OM (2 winners) = (a + 1) × (b + 1) − 1 − (a + b) + 2 × (a + b − 1) + (a − 1) + (b − 1) = (a + 1)(b + 1) + 2(a + b) − 5
or more simply as OM = ab + 3(a + b) − 4 - OM (1 winner) = 2 × (a − 1) = 2(a − 1)
- OM (4 winners) = (a + 1) × (b + 1) × (c + 1) × (d + 1) − 1 − (a + b + c + d) + 2 × [(a + b − 1) + (a + c − 1) + (a + d − 1) + (b + c − 1) + (b + d − 1) + (c + d − 1)]
= (a + 1)(b + 1)(c + 1)(d + 1) + 5(a + b + c + d) − 13 - OM (3 winners) = (a + 1) × (b + 1) × (c + 1) − 1 − (a + b + c) + 2 × [(a + b − 1) + (a + c − 1) + (b + c − 1)] + (a − 1) + (b − 1) + (c − 1) = (a + 1)(b + 1)(c + 1) + 4(a + b + c) − 10
- OM (2 winners) = (a + 1) × (b + 1) − 1 − (a + b) + 2 × (a + b − 1) + 2 × [(a − 1) + (b − 1)] = (a + 1)(b + 1) + 3(a + b) − 7
or more simply as OM = ab + 4(a + b) − 6 - OM (1 winner) = 3 × (a − 1) = 3(a − 1)
See also[edit]
Notes[edit]
- ^Sidney 1976, p.6
- ^Sidney 2003, p.13,36
- ^ abcdCortis, Dominic (2015). Expected Values and variance in bookmaker payouts: A Theoretical Approach towards setting limits on odds. Journal of Prediction Markets. 1. 9.
- ^Sidney 1976, p.96-104
- ^Sidney 2003, p.126-130
- ^Marek, Patrice (September 2018). 'Bookmakers' Efficiency in English Football Leagues'. Mathematical Methods in Economis - Conference Proceedings: 330–335.
- ^Sidney 1976, p.138-147
- ^Sidney 2003, p.163-177
- ^Sidney 1976, p.155-156
- ^Sidney 2003, p.170-171
- ^ abcSidney 1976, p.153-168
- ^ abcSidney 2003, p.169-177
- ^ abSidney 1976, p.166
- ^ abSidney 2003, p.169,176
- ^Sidney 1976, p.161
- ^Sidney 2003, p.176
References[edit]
- Cortis, D. (2015). 'Expected Values and variance in bookmaker payouts: A Theoretical Approach towards setting limits on odds'. Journal of Prediction Markets. 1. 9.
- Sidney, C (1976). The Art of Legging, Maxline International.
- Sidney, C (2003). The Art of Legging: The History, Theory, and Practice of Bookmaking on the English Turf, 3rd edition, Rotex Publishing 2003, 224pp. ISBN978-1-872254-06-7. Definitive, and extensively revised and updated 3rd edition on the history, theory, practice and mathematics of bookmaking, plus the mathematics of off-course betting, bets and their computation and liability control.
Further reading[edit]
- 'Finding an Edge', Ron Loftus, US-SC-North Charleston: Create Space., 2011, 144pp.
- 'How to make a book', Phil Bull, London: Morrison & Gibb Ltd., 1948, 160pp.
- 'The book on bookmaking', Ferde Rombola, California: Romford Press, 1984, 147pp. ISBN978-0-935536-37-9.
- The Art of Bookmaking, Malcolm Boyle, High Stakes Publishing 2006.
- Secrets of Successful Betting, Michael Adams, Raceform, 2002.
- The Mathematics of Games and Gambling, Edward W. Packel, Mathematical Association of America, 2006.
- The Mathematics of Gambling, Edward O. Thorp, L. Stuart, 1984.
- 'Maximin Hedges', Jean-Claude Derderian, Mathematics Magazine, volume 51, number 3. (May, 1978), pages 188–192.
- 'Carnap and de Finetti on Bets and the Probability of Singular Events: The Dutch Book Argument Reconsidered' Klaus Heilig, The British Journal for the Philosophy of Science, volume 29, number 4. (December, 1978), pages 325–346.
- 'Tests of the Efficiency of Racetrack Betting Using Bookmaker Odds', Ron Bird, Michael McCrae, Management Science, volume 33, number 12 (December, 1987), pages 152–156.
- 'Why is There a Favourite-Longshot Bias in British Racetrack Betting Markets', Leighton Vaughan Williams, David Paton. The Economic Journal, volume 107, number 440 (January, 1997), pages 150–158.
- Optimal Determination of Bookmakers' Betting Odds: Theory and Tests, by John Fingleton and Patrick Waldron, Trinity Economic Paper Series, Technical Paper No. 96/9, Trinity College, University of Dublin, 1999.
- 'Odds That Don't Add Up!', Mike Fletcher, Teaching Mathematics and its Applications, 1994, volume 13, number 4, pages 145–147.
- 'Information, Prices and Efficiency in a Fixed-Odds Betting Market', Peter F. Pope, David A. Peel, Economica, New Series, volume 56, number 223, (August, 1989), pages 323–341.
- 'A Mathematical Perspective on Gambling', Molly Maxwell, MIT Undergraduate Journal of Mathematics, volume 1, (1999), pages 123–132.
- 'Probability Guide to Gambling: The Mathematics of dice, slots, roulette, baccarat, blackjack, poker, lottery and sport bets', Catalin Barboianu, Infarom, 2006, 316pp. ISBN973-87520-3-5.
External links[edit]
Roulette is a game of numbers and chance. You can sit around studying the odds in roulette and the outcomes of trying to predict where that little ball will next end up but unfortunately you will be wasting a great deal of your time. Roulette is a game to be enjoyed. Sometimes you'll win and sometimes you'll lose. It's a game that has been played for centuries and no-one yet has found a way to truly beat the game. The game has been used to help develop statistical theories and processes such as Karl Pearson´s Goodness of Fit test. Could maths return the favour and help crack the code?
Countless people through the ages have tried to crack the roulette code using mathematics. Some of the more famous roulette systems are beased on mathematical sequences, strategies like the Fibonacci System, for example.
Math Behind Roulette
Mathematics seems the most obvious way in which you can attempt to beat the dealer but predicting any result is simply a matter of probability. The entire game is based upon independent events, which therefore means that any event that occurs when the wheel spins and the ball lands has no affect or influence on any previous or future spin. You should also check out our page that covers physics in roulette, by the way.
In European Roulette the payout on hitting any one of the 36 red or black numbers on the wheel is 35 to 1. It's the highest payout you can achieve with a single bet and so of course means that the probability is the lowest (at just 2.7% in fact). For an averagely better chance of winning many players will simply place an even-money bet on something like red or black, odds or evens or any one of the numbered groups. The probability is a massive 48.6% but the payout is just 1:1. But if the bet is pretty much a 50-50 chance then why is it only 48.6% and not 50%? Well, don't forget that the European table also includes the green zero pocket so this does mean that the odds will be slightly lower than 50/50. In fact, this little zero pocket is what gives the casino its roulette house edge, when combined with the payout structure.
British engineer Joseph Jagger did manage to use mathematics and predictability when he managed to win a significant sum of money on his visit to Monte Carlo in 1875. Jagger has hired 6 clerks to visit the casino Beaux-Arts Casino in Monaco to record all the outcomes of 6 different roulette wheels over a period of time. Using these findings he was able to discover a pattern of a group of numbers that kept coming in more frequently than others on just one of these wheels. He ended up placing his bets on this particular wheel using these numbers in question and was able to accumulate hundreds and thousands of pounds of winnings.
Math Behind Roulette
However, Jagger hadn't uncovered an incredible flaw in the game itself. He had simply exposed the fact a roulette wheel in the world's biggest gambling capital merely had a mechanical imbalance which gave the wheel a clear bias towards certain outcomes. And the problem with that discovery, was that the casino discovered it as well. And they fixed the wheel!